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What is the area of a triangle with the vertices (-6,-1), (6,3), and (-3,10)?

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Final answer:

The area of the triangle with vertices (-6,-1), (6,3), and (-3,10) is 60 square units. This is calculated using the formula for the area of a triangle given its vertices.

Step-by-step explanation:

To find the area of a triangle given its vertices, we can use the formula for the area of a triangle using coordinates.

The formula is:

Area = 1/2 * abs((x1 * (y2-y3) + x2 * (y3-y1) + x3 * (y1-y2)))

In this case, the vertices of the triangle are (-6,-1), (6,3), and (-3,10). By substituting these values into the formula, we can calculate the area of the triangle.

Area = 1/2 * abs((-6 * (3-10) + 6 * (10-(-1)) + (-3) * ((-1)-3)))

Area = 1/2 * abs((-6 * -7 + 6 * 11 + -3 * -4))

Area = 1/2 * abs((42 + 66 + 12))

Area = 1/2 * abs(120)

Area = 1/2 * 120

Area = 60 square units

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