Final answer:
To determine the volume of the gold medal, the formula for the volume of a cylinder is used, where the volume is the product of pi, the square of the radius, and the height (thickness). The volume is found to be 2.7π cm³.
Step-by-step explanation:
To calculate the volume of a gold medal, we use the volume formula for a cylinder: V = πr²h, where 'V' is the volume, 'r' is the radius, and 'h' is the height (or thickness in this case). The diameter of the medal is 60 mm, therefore the radius is half of that, which is 30 mm or 3 cm (since 10 mm equals 1 cm). The thickness is 3 mm, which is equivalent to 0.3 cm. Now, we plug these values into the formula to find the volume, V = π(3 cm)²(0.3 cm) = π(9 cm²)(0.3 cm) = 2.7π cm³.
Given that the density of gold is 19 g/cm³, we can understand that this physical property helps relate mass and volume, as seen in previous examples. However, since the question asks for volume and we've calculated it, no further use of density is required unless we were asked to find mass.