Final answer:
The heat required to increase the temperature of the 7.10 kg block of aluminum from 13.0°C to 47.0°C is 23,274 Joules.
Step-by-step explanation:
To calculate the heat required to increase the temperature of the aluminum block, we can use the formula:
Q = m * c * ΔT
Where:
- Q is the heat (in Joules)
- m is the mass of the block (in kg)
- c is the specific heat of aluminum (in J/kg°C)
- ΔT is the change in temperature (in °C)
Substituting the given values into the formula:
Q = (7.10 kg) * (900 J/kg°C) * (47.0°C - 13.0°C)
Q = 23,274 J
Therefore, the heat required to increase the temperature of the 7.10 kg block of aluminum from 13.0°C to 47.0°C is 23,274 Joules.