15.9k views
5 votes
What is the molar concentration of potassium ions in a 0.250 M K₂SO₄(aq) solution? Remember that SO₄²- is the polyatomic ion sulfate.

1 Answer

4 votes

Final answer:

The molar concentration of potassium ions in a 0.250 M K₂SO₄ solution is 0.500 M, because the dissolution of K₂SO₄ produces two moles of K⁺ ions for every mole of the compound dissolved.

Step-by-step explanation:

To calculate the molar concentration of potassium ions in a 0.250 M K₂SO₄(aq) solution, we should understand that each unit of K₂SO₄ dissociates into two potassium ions (2 K⁺) and one sulfate ion (SO₄²⁻). Therefore, for every mole of K₂SO₄ that dissolves, two moles of potassium ions are released into the solution.

Given that the concentration of K₂SO₄ is 0.250 M, we can set up the proportion as follows:

  • 1 mole of K₂SO₄ produces 2 moles of K⁺ ions
  • Therefore, 0.250 M K₂SO₄ will produce 0.250 M × 2 = 0.500 M of K⁺ ions

Thus, the molar concentration of potassium ions in the solution is 0.500 M.

User Nsinghphd
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.