Final answer:
The energy required to increase the temperature of a 7.10-kg block of aluminum from 13.0°C to 47.0°C is 217,980 joules. The calculation uses the specific heat of aluminum, the mass of the block, and the change in temperature.
Step-by-step explanation:
The student has asked about the heat (energy) required to increase the temperature of a 7.10-kg block of aluminum from 13.0°C to 47.0°C, given that the specific heat of aluminum is 900 J/kg°C. To calculate this, the formula to use is Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature.
In this case, the change in temperature (ΔT) is 47.0°C - 13.0°C = 34.0°C. Hence, the heat energy (Q) required can be calculated as follows:
Q = (7.10 kg)(900 J/kg°C)(34.0°C)
Q = 217,980 J
Therefore, 217,980 joules of energy is required to increase the temperature of a 7.10-kg block of aluminum from 13.0°C to 47.0°C.