Question

What is the force on gamma by alpha? Give the magnitude of the force in μn (micronewtons) and the direction as an angle measured counterclockwise (ccw) from the starboard direction. The angle can be between 0 and 180 degrees. If the angle must be measured clockwise (cw) from the starboard direction, give a negative angle.

Answer 1

The force on gamma by alpha is determined by the interaction between the magnetic field and the motion of the alpha-particle. The force experienced by the alpha-particle can be calculated using the formula F = qvBsinθ. For the given situations, the force on gamma by alpha is 0 μN.

Step-by-step explanation:

The force on gamma by alpha is determined by the interaction between the magnetic field and the motion of the alpha-particle. The force experienced by the alpha-particle can be calculated using the formula F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the magnitude of the magnetic field, and θ is the angle between the velocity and the magnetic field.

For part (a), since the alpha-particle is moving in the positive x-direction, the angle θ between its velocity and the magnetic field is 90 degrees, resulting in a force of 0 μN.

For part (b), since the alpha-particle is moving in the negative y-direction, the angle θ is 0 degrees, resulting in a force of 0 μN.

For part (c), since the alpha-particle is moving in the positive z-direction, the angle θ is also 0 degrees, resulting in a force of 0 μN.

For part (d), the velocity vector is given as (2.0î – 3.0ĵ + 1.0k) × 10¹ m/s. The angle between the velocity and the magnetic field is 90 degrees, resulting in a force of 0 μN.