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What is the final temperature (in °c) of 410.1 g of water (specific heat = 4.184 j/g⋅ °c) at 24.20 °c that absorbed 950.0 j of heat?

User Subhas
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1 Answer

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Final answer:

The final temperature of the water after it has absorbed 950.0 J of heat is 24.75°C.

Step-by-step explanation:

To find the final temperature of 410.1 g of water after absorbing 950.0 J of heat, we employ the heat capacity formula:

q = m × c × ΔT

where q is the heat energy absorbed, m is the mass of the water, c is the specific heat capacity, and ΔT is the change in temperature.

Rearranging for ΔT:

ΔT = q / (m × c)

By substituting the given values:

ΔT = 950.0 J / (410.1 g × 4.184 J/g°C)

ΔT = 950.0 J / 1716.9784 J°C

ΔT = 0.55°C

Now, add the temperature change to the initial temperature to find the final temperature:

Final Temperature = Initial Temperature + ΔT

Final Temperature = 24.20°C + 0.55°C

Final Temperature = 24.75°C

The final temperature of the water after absorbing 950.0 J of heat is 24.75°C.

User NONEenglisher
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