Question

Potassium chloride reacts with silver nitrate to produce solid silver chloride and potassium nitrate.

KCl(aq) + AgNO3(aq) → AgCl(s) + KNO3(aq)
How many grams of KCl are required to react completely with 250 mL of 0.030 M AgNO3?
a) 2.63 g
b) 13.18 g
c) 0.1018 g
d) 3.358 g
e) 0.1128 g
f) 0.559 g

Answer 1

To find the number of grams of KCl required to react completely with 250 mL of 0.030 M AgNO3, you need to use stoichiometry. The correct answer is 2.63 grams.

Step-by-step explanation:

To find the number of grams of KCl required to react completely with 250 mL of 0.030 M AgNO3, you need to use stoichiometry. First, convert the volume of AgNO3 to moles using the equation:

Moles = volume (L) x concentration (M)

Then, use the balanced equation to determine the mole ratio between KCl and AgNO3. The ratio is 1:1, so the number of moles of KCl required will be the same as the moles of AgNO3. Finally, convert moles of KCl to grams using its molar mass.

The correct answer is 2.63 grams.