Question

If the ultimate BOD of two wastes having k values of 0.0800 d⁻¹ and 0.120 d⁻¹ is 280.0 mg/L, what would be the 5-day BOD for each?

Answer 1

To find the 5-day BOD for each waste, use the formula BOD5 = ultimate BOD / (e^-k * 5).

Step-by-step explanation:

To find the 5-day BOD for each waste, we can use the formula:

BOD5 = ultimate BOD / (e^-k * 5)

For the waste with a k value of 0.0800 d⁻¹, the BOD5 would be:

BOD5 = 280.0 mg/L / (e^(-0.0800 * 5))

For the waste with a k value of 0.120 d⁻¹, the BOD5 would be:

BOD5 = 280.0 mg/L / (e^(-0.120 * 5))