Question

An electric field of magnitude 3.30 kN/C is applied along the x axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true.

(a) The plane is parallel to the yz plane.
N.m²/C
(b) The plane is parallel to the xy plane.
N.m²/C
(c) The plane contains the y axis, and its normal makes an angle of 37.4° with the x axis.
N-m²/C

Answer 1

To calculate the electric flux through a rectangular plane, multiply the electric field magnitude by the area of the plane and the cosine of the angle between the electric field and the plane's normal.

Step-by-step explanation:

The electric flux through a rectangular plane can be calculated by multiplying the electric field magnitude by the area of the plane and the cosine of the angle between the electric field and the plane's normal. For part (a), since the plane is parallel to the yz-plane, its normal is perpendicular to the x-axis, so the angle between the electric field and the plane's normal is 90°. Therefore, the electric flux is 0 N.m²/C.

For part (b), since the plane is parallel to the xy-plane, its normal is perpendicular to the z-axis, so the angle between the electric field and the plane's normal is 30°. Therefore, the electric flux is (3.30 kN/C)(0.350 m)(0.700 m)(cos(30°)).

For part (c), the angle between the electric field and the plane's normal is 37.4°. Therefore, the electric flux is (3.30 kN/C)(0.350 m)(cos(37.4°)).