Question

Perfectly rigid containers each hold n moles of ideal gas, one being hydrogen H2 and other being neon Ne.

If it takes 100 J of heat to increase the temperature of the hydrogen by 3.50?C, by how many degrees will the same amount of heat raise the temperature of the neon?

Answer 1

The amount of degree celsius the same amount of heat will raise the temperature of the neon to, is 5.7 °C

How to determine the temperature rise of neon?

First, we shall calculate the number of mole of H₂ in the container. This is shown below:

• Heat added (Q) = 100 J
• Temperature rise of H₂ (ΔT) = 3.50 °C
• Molar heat capacity of H₂ (C) = 20.4 J/molK
• Number of mole of H₂ (n) =?

`n = (Q)/(C\Delta T) \\\\n = (100)/(20.4\ *\ 3.5)\\\\n = 1.4\ mole`

Now, we shall obtain the temperature rise for Ne. This is shown below:

• Heat added (Q) = 100 J
• Number of mole of H₂ = 1.4 mole
• Number of mole of Ne (n) = Number of mole of H₂ = 1.4 mole
• Molar heat capacity of Ne (C) = 12.5 J/molK
• Temperature rise of Ne (ΔT) = ?

`\Delta T = (Q)/(nC) \\\\\Delta T = (100)/(1.4\ *\ 12.5)\\\\\Delta T = 5.7\ \textdegree C`