40.3k views
4 votes
Two particles, one with charge −5.45 μC and one with charge 3.55 μC, are 5.84 cm apart. What is the magnitude of the force that one particle exerts on the other? 511.1 N

1 Answer

7 votes

Final answer:

The magnitude of the force between the two particles is 511.1 N.

Step-by-step explanation:

To calculate the magnitude of the force between two charged particles, we can use Coulomb's Law:

F = k * |q1 * q2| / r^2

where F is the force, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

In this case, we have q1 = -5.45 μC, q2 = 3.55 μC, and r = 5.84 cm (or 0.0584 m).

Plugging in these values gives us:

F = (9 x 10^9 Nm^2/C^2) * |-5.45 x 10^-6 C * 3.55 x 10^-6 C| / (0.0584 m)^2

= 511.1 N

Therefore, the magnitude of the force that one particle exerts on the other is 511.1 N.

User XOneca
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.