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Two particles, one with charge −5.45 μC and one with charge 3.55 μC, are 5.84 cm apart. What is the magnitude of the force that one particle exerts on the other? 511.1 N

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Final answer:

The magnitude of the force between the two particles is 511.1 N.

Step-by-step explanation:

To calculate the magnitude of the force between two charged particles, we can use Coulomb's Law:

F = k * |q1 * q2| / r^2

where F is the force, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

In this case, we have q1 = -5.45 μC, q2 = 3.55 μC, and r = 5.84 cm (or 0.0584 m).

Plugging in these values gives us:

F = (9 x 10^9 Nm^2/C^2) * |-5.45 x 10^-6 C * 3.55 x 10^-6 C| / (0.0584 m)^2

= 511.1 N

Therefore, the magnitude of the force that one particle exerts on the other is 511.1 N.

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