Question

A block of weight W is pulled along a horizontal surface at constant speed v by a force F, which acts at an angle of with the horizontal, as shown above. The normal force exerted on the block by the surface has magnitude

a.W - Fcos
b.W - Fsin
c.W
d.W + Fsin
e.W + Fcos

Answer 1

In Physics, when a force pulls a block at an angle on a horizontal surface, the normal force is found by considering the vertical components of all the forces acting on the block.

Step-by-step explanation:

The question deals with the concept of forces and motion in Physics. Specifically, it relates to a scenario where a block of weight W is pulled along a horizontal surface with a force F acting at an angle. To determine the normal force exerted on the block by the surface, it is important to understand how forces are resolved into components. The force F has both a horizontal component (F cos) and a vertical component (F sin).

Since the block is moving at a constant speed, the net force in the horizontal direction is zero, and the frictional force equals the horizontal component of F. In the vertical direction, the normal force N plus the vertical component of F must balance the weight of the block W.

Answer 2

The question pertains to the normal force on a block being pulled at an angle on a horizontal surface. The correct normal force would be the weight of the block minus the vertical component of the pulling force, which is W - F sin(θ). This concept is grounded in the physics of forces and motion.

Step-by-step explanation:

The question involves understanding the concept of forces and motion on a horizontal surface, which relates to the physics principles of Newton's laws, specifically analyzing the normal force experienced by a block. When a block of weight W is pulled along a horizontal surface by a force F at an angle, the gravitational force would equal the normal force if there were no inclination or additional forces at play apart from F. Considering the force F has a component acting vertically (upward or downward), it will affect the normal force exerted by the surface on the block.

In this scenario, the normal force is W - F sin(θ), assuming no other vertical forces besides W and the vertical component of F. The sine component of force F reduces the normal force because it counteracts part of the weight. When pulling upward at an angle, the vertical component of the pulling force relieves some of the weight from the surface, thus decreasing the normal force.