Final answer:
To make 500 mL of 0.1 M NaOH, you need 8.3 mL of 6M NaOH. To determine the amount of DI water required, subtract the volume of 6M NaOH from the total volume.
Step-by-step explanation:
To determine the amount of 6M NaOH required to make 500 mL of 0.1M NaOH, we can use the equation:
C1V1 = C2V2
Where C1 = initial concentration, V1 = initial volume, C2 = final concentration, and V2 = final volume.
Plugging in the values:
6M(NaOH)(V1) = 0.1M(NaOH)(500 mL)
V1 = (0.1M(NaOH)(500 mL))/(6M(NaOH)) = 8.3 mL
To determine the amount of DI water required, we can subtract the volume of 6M NaOH from the total volume desired:
Volume of DI Water = 500 mL - 8.3 mL = 491.7 mL