Final answer:
To charge the 1.00 μF capacitor and store 1.20 J of energy, you should charge it to approximately 1.55V.
Step-by-step explanation:
To calculate the potential to charge a 1.00 μF capacitor and store 1.20 J of energy, we can use the formula:
E = (1/2)CV²
Where E is the energy stored, C is the capacitance, and V is the potential difference. Rearranging the formula, we have:
V = √(2E/C)
Plugging in the given values, we get:
V = √(2 * 1.20 J / 1.00 μF)
V = √(2 * 1.20 * 10^(-6) F / 1.00 * 10^(-6) F)
V = √(2.40)
V ≈ 1.55V