Final answer:
The rate of change of O₂ concentration is -0.0165M/s. The rate of change of H₂O concentration is -0.033M/s. The rate of change of S₈ concentration is -0.033M/s. The rate of the reaction is -0.033M/s.
Step-by-step explanation:
The reaction rate can be determined by looking at the coefficients of the balanced equation, which give us the ratio of reactant to product. In this case, the ratio is 8:4, or 2:1. This means that for every 2 moles of H₂S that react, 1 mole of O₂ is consumed. Therefore, the rate of change of O₂ concentration is half of the rate of change of H₂S concentration, so Δ[O₂]/Δt = -0.033M/s * (1/2) = -0.0165M/s.
Similarly, for every 8 moles of H₂S that react, 8 moles of H₂O and 1 mole of S₈ are produced. Therefore, the rate of change of H₂O concentration is equal to the rate of change of H₂S concentration, so Δ[H₂O]/Δt = -0.033M/s.
Finally, the rate of change of S₈ concentration is determined by the stoichiometric coefficient, which is 1. Therefore, Δ[S₈]/Δt = -0.033M/s.
The overall rate of the reaction can be expressed in terms of any of the reactants or products. In this case, the rate of change of H₂S is given, so the rate of the reaction is -0.033M/s.