Final answer:
The electric field strength at the position (x,y) = (5.0 cm, 0 cm) due to a +14 nC charge located at the origin can be calculated using Coulomb's law.
Step-by-step explanation:
The strength of the electric field at the position (x,y) = (5.0 cm, 0 cm) due to a +14 nC charge located at the origin can be calculated using Coulomb's law. The formula to calculate the electric field is given by:
E = k * (Q / r²)
where E is the electric field strength, k is the electrostatic constant (9 x 10^9 Nm²/C²), Q is the charge (in this case +14 nC = 14 x 10^-9 C), and r is the distance between the charges (in this case 5.0 cm = 0.05 m).
Plugging in the values, we get:
E = (9 x 10^9 Nm²/C²) * (14 x 10^-9 C) / (0.05 m)²
Simplifying this gives us:
E = (9 x 10^9 Nm²/C²) * (14 x 10^-9 C) / (0.0025 m²)
Calculating this gives us the strength of the electric field at the given position.