Final answer:
The voltage drop across the 6.5Ω resistor in the RL series circuit is approximately 78 volts.
Step-by-step explanation:
In an RL series circuit, the voltage drop across the resistor can be found using Ohm's law by multiplying the resistance value (6.5Ω) by the current flowing through it (12A).
Voltage drop = Resistance x Current
Voltage drop = 6.5Ω x 12A = 78V
Therefore, the voltage drop across the resistor is approximately 78 volts.