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An RL series circuit contains a resistor and an inductor. The resistor has a value of 6.5Ω. The circuit is connected to 120V and has a current flow of 12A. What is the voltage drop across the 6.5Ω resistor to the nearest volt?

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Final answer:

The voltage drop across the 6.5Ω resistor in the RL series circuit is approximately 78 volts.

Step-by-step explanation:

In an RL series circuit, the voltage drop across the resistor can be found using Ohm's law by multiplying the resistance value (6.5Ω) by the current flowing through it (12A).

Voltage drop = Resistance x Current

Voltage drop = 6.5Ω x 12A = 78V

Therefore, the voltage drop across the resistor is approximately 78 volts.

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