Question

A train travels 8.81 m/s in a -51.0 degree direction. The train accelerates for 2.23 s, changing its velocity to 9.66 m/s in a 37 degree direction. What is the change in position (delta x)?

Answer 1

The change in position (delta x) of the train is 20.586 meters.

Step-by-step explanation:

To find the change in position (delta x) of the train, we can use the equations of motion. We know that the train accelerated for 2.23 s, changing its velocity from 8.81 m/s in a -51.0 degree direction to 9.66 m/s in a 37 degree direction.

To calculate the change in position, we need to find the average velocity of the train during the acceleration. We can find the change in position using the formula:

delta x = average velocity * time

Let's calculate:

average velocity = (initial velocity + final velocity) / 2

average velocity = (8.81 m/s + 9.66 m/s) / 2 = 9.235 m/s

delta x = average velocity * time = 9.235 m/s * 2.23 s = 20.586 m

Therefore, the change in position of the train is 20.586 meters.