Final answer:
To calculate the new volume of the weather balloon at a lower temperature, we used Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin. We found that the volume will decrease to approximately 140.3 liters after rising to the altitude where the temperature is -8.00°C.
Step-by-step explanation:
The student's question involves the concept of the behavior of gases under different temperatures, described by Charles's Law. According to Charles's Law, if the pressure is constant, the volume of a gas is directly proportional to its temperature measured in Kelvin. We can express this as V1/T1 = V2/T2, where V1 and T1 represent the initial volume and temperature of the gas, and V2 and T2 represent the final volume and temperature of the gas.
To find the new volume of the weather balloon at the altitude with a temperature of -8.00°C, we first convert both temperatures to Kelvin. The initial temperature is 10°C (283.15 K) and the final temperature is -8°C (265.15 K). We can then rearrange Charles's Law to solve for V2, which gives us V2 = V1 * (T2/T1).
Substituting the given values, we get V2 = 150.0 L * (265.15 K / 283.15 K). Calculating this yields a final volume of approximately 140.3 liters. Therefore, the volume of the weather balloon will decrease when it rises to the altitude with a lower temperature.