Question

A proton in a linear accelerator has a de broglie wavelength of 122 pm. What is the de broglie wavelength of the proton in meters?

Answer 1

The de Broglie wavelength of a proton can be calculated using the equation λ = h / p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the proton. To convert the de Broglie wavelength of 122 pm to meters, divide by 10^12. Therefore, the de Broglie wavelength of the proton is 1.22 × 10^-10 m.

Step-by-step explanation:

The de Broglie wavelength of a proton can be calculated using the equation:

λ = h / p

Where λ is the wavelength, h is Planck's constant (6.626 × 10-34 m2 kg / s), and p is the momentum of the proton.

To convert the de Broglie wavelength of 122 pm to meters, divide by 1012:

λ = 122 pm / 1012 = 1.22 × 10-10 m

Therefore, the de Broglie wavelength of the proton is 1.22 × 10-10 m.