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A tennis ball thrown at a velocity of 25m/s lands exactly 3s later on the top of a building. What is the height of the building?

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Final answer:

The height of the building is 87.5 meters.

Step-by-step explanation:

To calculate the height of the building, we can use the equation for projectile motion. First, we need to find the time it takes for the ball to reach the top of the building. Since the ball is thrown horizontally with a velocity of 25m/s, the time it takes to reach the building is the same as the time it takes to fall back down. Using the equation d = (1/2)gt^2, where d is the distance, g is the acceleration due to gravity (9.8 m/s^2), and t is the time, we can solve for t:

d = (1/2)gt^2

60 = (1/2)(9.8)(t^2)

t^2 = 12.24

t = 3.5s

Now we can find the height of the building using the equation d = vt, where d is the distance, v is the velocity, and t is the time:

d = vt

d = 25 * 3.5

d = 87.5m

Therefore, the height of the building is 87.5 meters.

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