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A motorcycle accelerates from rest to 18 m/s in 56 s. What was the cyclist's average velocity?

User Farhood ET
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1 Answer

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Final answer:

The cyclist's average velocity when accelerating from rest to 18 m/s over 56 seconds is 9 m/s, using the formula for average velocity of (u + v)/2, where u is 0 m/s (starting from rest) and v is 18 m/s.

Step-by-step explanation:

The student has asked to determine the cyclist's average velocity when a motorcycle accelerates from rest to a speed of 18 m/s over a period of 56 seconds. To find the average velocity, you would use the formula for average velocity when starting from rest, which is v = (u + v)/2, where u is the initial velocity and v is the final velocity. Since the motorcycle starts from rest, u is 0 m/s, and the final velocity v is 18 m/s. Thus, the average velocity would be (0 + 18)/2 = 9 m/s.

User Chantese
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