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How many grams of carbon dioxide do you get from 429 g of glucose: C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O?

User Artch
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Final answer:

Approximately 1026.95 grams of carbon dioxide are produced from 429 grams of glucose.

Step-by-step explanation:

To find the grams of CO₂ produced from 429 g of glucose, we need to use the molar ratio from the balanced chemical equation. From the equation C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O, we can see that 1 mole of glucose reacts to yield 6 moles of CO₂. The molar mass of glucose is 180.16 g/mol and the molar mass of CO₂ is 44.01 g/mol. Using these values, we can set up a proportion:

(429 g of glucose) / (180.16 g/mol of glucose) = (x g of CO₂) / (44.01 g/mol of CO₂)

Solving for x, we get approximately 1026.95 g of CO₂.

User ThePixelPony
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