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One end of a 62-cm-long copper rod with a diameter of 2.2 cm is kept at 500 °C, and the other is immersed in water at 24 °C. Calculate the heat conduction rate along the rod.

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Final answer:

The heat conduction rate along the copper rod depends on the thermal conductivity, cross-sectional area, temperature difference, and length of the rod. The heat conduction rate in this case is approximately -11501.72 W.

Step-by-step explanation:

The heat conduction rate along the copper rod can be calculated using the formula:

Q = -k * A * ΔT / L

Where:

  • Q is the heat conduction rate
  • k is the thermal conductivity of copper
  • A is the cross-sectional area of the rod
  • ΔT is the temperature difference between the ends of the rod
  • L is the length of the rod

In this case, the thermal conductivity of copper is approximately 401 W/m·K. The cross-sectional area of the rod can be calculated using the formula:

A = π * (d/2)^2

Where:

  • d is the diameter of the rod

Substituting the given values into the formula, we have:

A = π * (2.2/2)^2 = 3.801 cm^2

ΔT = (500 - 24) °C = 476 °C

L = 62 cm

Plugging in the values, we get:

Q = -401 W/m·K * 3.801 cm^2 * 476 °C / 62 cm = -11501.72 W

The heat conduction rate along the rod is approximately -11501.72 W.

User Dmitry Perets
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