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0.10 mol of argon gas is admitted to an evacuated 50 cm³ container at 20°c. The gas then undergoes an isobaric heating to a temperature of 250 °c. What is the final volume of the gas?

User Wael
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Final answer:

The final volume of the gas can be determined using the ideal gas law formula, which takes into account the initial volume, number of moles, initial and final temperatures, and constant pressure of the gas.

Step-by-step explanation:

The final volume of the gas can be determined using the ideal gas law formula, which states that:

V = nRT/P

Where:

  • V is the volume of the gas
  • n is the number of moles of the gas
  • R is the ideal gas constant (8.314 J/(mol·K))
  • T is the temperature of the gas in Kelvin
  • P is the pressure of the gas

In this case, the initial volume (V1) is 50 cm³ (which can be converted to liters by dividing by 1000), the initial number of moles (n1) is 0.10 mol, the initial temperature (T1) is 20°C (which can be converted to Kelvin by adding 273), the final temperature (T2) is 250°C, and the pressure (P) is constant throughout the process.

Using the formula:

V2 = (n1 × R × T2) / (P × T1)

Plugging in the values:

V2 = (0.10 × 8.314 × (250 + 273)) / (1 × (20 + 273))

V2 = 2.37 L

Therefore, the final volume of the gas is 2.37 liters.

User Samee
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