13.0k views
1 vote
A gas with a volume of 5.5L at a pressure of 2.1 atm is allowed to expand to a volume of 12L. What is the pressure in the container if the temperature remains constant

User Danjarvis
by
8.2k points

1 Answer

2 votes

Final answer:

Using Boyle's Law, which states that pressure and volume are inversely proportional (P1V1=P2V2) at constant temperature, we calculated the final pressure to be 0.9625 atm when a gas that initially had a volume of 5.5L at a pressure of 2.1 atm is allowed to expand to a volume of 12L.

Step-by-step explanation:

The question relates to the behavior of gases and their properties under different conditions, specifically when the volume changes and the temperature remains constant. To find the final pressure when a gas expands from 5.5L to 12L while maintaining a constant temperature, we can use Boyle's Law. Boyle's Law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume when the temperature remains constant (P1V1=P2V2).

To find the new pressure (P2) when the volume changes from 5.5L to 12L, with an initial pressure (P1) of 2.1 atm, we rearrange the formula to solve for P2:

P1 × V1 = P2 × V2

So,

P2 = (P1 × V1) / V2

P2 = (2.1 atm × 5.5L) / 12L

P2 = 0.9625 atm

The final pressure in the container after the expansion is 0.9625 atm.

User Blenderfreaky
by
8.2k points