The value of x in triangle ABC is 4.
In triangle ABC, let's use the given property that the exterior angle at vertex C (angle ACM) is equal to the sum of the interior opposite angles (angle BAC and angle ABC). Mathematically, this is expressed as:
![\[ \text{Angle ACM} = \text{Angle BAC} + \text{Angle ABC} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/hqet0v3bfuwofvrllb94dkjva5flekvqa6.png)
Substitute the given expressions for these angles:
(x + 2) = (2x - 8) + (3x - 6)
Combine like terms:
x + 2 = 5x - 14
Isolate the variable:
4x = 16
Solve for x:
x = 4
So, the value of x is 4.
The probable question may be:
In triangle ABC , Angle BAC=(2x-8), angle ABC=(3x-6) line BC is extended outside the triangle as CM and angle ACM=(x+2) Find the value of x?