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Ice tea flowing through a pipe at the rate of 80 kg/min is sweetened by adding sugar solution (which contains 30?

User Gmc
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1 Answer

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Final Answer:

1. Sugar Solution Needed: 12 kg/min.

2. Water Removed in Evaporator: 68 kg/hour.

3. Sugar Concentration in Concentrated Ice Tea: 20%.

Step-by-step explanation:

1. To achieve 5% sugar in the final product, you need to find the amount of sugar solution to add. The difference between the initial sugar content (30%) and the desired concentration (5%) is 25%. Multiplying this percentage by the rate of ice tea flow (80 kg/min) gives the required sugar solution: 80 kg/min x 25% = 12 kg/min.

2. In the evaporator, the output is concentrated ice tea. The difference between the input (80 kg/min) and output (40 kg/hour) gives the amount of water removed: 80 kg/min - 40 kg/hour = 68 kg/hour.

3. The sugar concentration in the concentrated ice tea can be found by subtracting the water content from the initial sugar content: 30% - 10% (100% - 30% - 60% water content) = 20%.

Your question is incomplete, but most probably your full question was Ice Tea Flowing Through A Pipe At The Rate Of 80 Kg/Min Is Sweetened By Adding Sugar Solution (Which Contains 30% Sugar) Into The Pipe. How Much Sugar Solution Should Be Added To Have 5% Sugar In The Product? The Product Is Then Channeled In An Evaporator To Produce Concentrated Ice Tea. If The Output Of The Evaporator Is 40 Kg Concentrated Ice Tea /Ice tea flowing through a pipe at the rate of 80 kg/min is sweetened by adding sugar solution (which contains 30% sugar) into the pipe. How much sugar solution should be added to have 5% sugar in the product? The product is then channeled in an evaporator to produce concentrated ice tea. If the output of the evaporator is 40 kg concentrated ice tea /hour, how much water is removed per hour? What is the sugar concentration of the concentrated ice tea?

User Hessuew
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