Final answer:
To make ice cubes from 0.96 kg of water at 0 Celsius, 320.64 kJ of energy must be removed, using the latent heat of fusion for water which is 334 kJ/kg.
Step-by-step explanation:
To calculate how much thermal energy must be removed from 0.96 kg of water at 0 Celsius to make ice cubes at the same temperature, one must consider the latent heat of fusion for water. The latent heat of fusion for water is approximately 334 kJ/kg. Therefore, the amount of energy required to freeze 0.96 kg of water can be calculated using the formula:
Q = m × Lf
Where:
Q is the quantity of heat (in kJ),
m is the mass of the water (in kg), and
Lf is the latent heat of fusion for water (kJ/kg).
plugging in the values, we get:
Q = (0.96 kg) × (334 kJ/kg) = 320.64 kJ
Thus, 320.64 kJ of energy must be removed to turn 0.96 kg of water at 0 Celsius into ice cubes at the same temperature.