Final answer:
To find the amount of HCl required to react with Zn, use stoichiometry and the balanced chemical equation. Convert the mass of Zn to moles, use the mole ratio to find the moles of HCl, then convert to milliliters using the molarity of HCl.
Step-by-step explanation:
To find the amount of HCl required to react with Zn, we need to use stoichiometry and the balanced chemical equation for the reaction. The balanced equation is:
Zn + 2HCl --> ZnCl2 + H2
From the balanced equation, we can see that 1 mole of Zn reacts with 2 moles of HCl. First, we need to convert the given mass of Zn to moles:
9.85 g Zn * (1 mole Zn / atomic mass of Zn) = X moles Zn
Next, we can use the mole ratio from the balanced equation to find the moles of HCl:
X mol Zn * (2 mol HCl / 1 mol Zn) = Y moles HCl
Finally, we can convert the moles of HCl to milliliters by using the molarity of HCl. If the concentration of HCl is known, we can use the formula:
Y moles HCl * (1000 mL / molarity of HCl) = Z mL HCl
Make sure to substitute the correct values and units into the equation to get the final answer in milliliters.