Question

Given the chemical equation 2Fe + 3Cl₂ → 2FeCl3, how many moles of chlorine gas will be required to react with sufficient iron to produce 7 moles of iron (III) chloride?

Answer 1

To produce 7 moles of iron (III) chloride, 10.5 moles of chlorine gas are required.

Step-by-step explanation:

To determine how many moles of chlorine gas are required to react with sufficient iron to produce 7 moles of iron (III) chloride, we need to use the stoichiometry of the balanced chemical equation. The equation tells us that 2 moles of iron react with 3 moles of chlorine gas to produce 2 moles of iron (III) chloride. This means that the mole ratio of chlorine gas to iron (III) chloride is 3:2. To calculate the number of moles of chlorine gas needed, we can set up a proportion:

1. 
   
3. 3 moles Cl₂ / 2 moles FeCl₃ = x moles Cl₂ / 7 moles FeCl₃
4. 
   
6. Cross-multiply and solve for x:
7. 
   

• 
  
• x = (3 moles Cl₂ / 2 moles FeCl₃) * 7 moles FeCl₃
• 
  
• x = 10.5 moles Cl₂
•