87.0k views
2 votes
George backed into his neighbor's bikes while backing his vehicle out and crashed. What distance did he crash into the bikes?

1) 100 meters
2) 200 meters
3) 300 meters
4) 400 meters

User Jcity
by
7.1k points

1 Answer

5 votes

Final answer:

The question about George crashing into bikes lacks information to solve. For the other related physics problems, kinematic equations are employed to find final velocity, time saved, and positions relative to other racers. For distance conversions, meters are multiplied by 100 to get centimeters.

Step-by-step explanation:

The original question about George backing into his neighbor's bikes and the distance he crashed into them does not provide sufficient information to determine the distance. However, the reference information given is related to physics problems involving velocity, acceleration, distance, and time. Here, it appears that the student might be confused or mixed several different questions into one. To solve physics questions involving motion, one typically uses equations of kinematics such as v = u + at for final velocity (where v is final velocity, u is initial velocity, a is acceleration, and t is time) and the equation for distance traveled under constant acceleration, d = ut + 1/2 at2.

For the given situation where a bicycle racer has an initial velocity of 11.5 m/s and accelerates at 0.500 m/s² for 7.00 s, the final velocity (v) can be calculated using the formula v = u + at. Subsequently, knowing the final velocity, the time saved to cover 300 m can be calculated. Additionally, the second racer's position and time to finish can be determined based on his constant speed and the distance to be covered.

In questions related to distances like the one from Calvin's house, one would convert the distance from meters to centimeters by multiplying by 100, since 1 meter equals 100 centimeters.

User Trinu
by
7.9k points