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From a cask filled with wine, 75 litres are first drawn and replaced with water. From this mixture, 60 litres are drawn and replaced with water. The ratio of wine to water in the cask is now 3/2. How many litres of wine did the cask initially hold?

User Teoreda
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Final answer:

To find the initial amount of wine in the cask, we can set up an equation based on the given information and solve for x. The cask initially held 180 liters of wine.

Step-by-step explanation:

Let's assume the initial amount of wine in the cask is represented by x liters.

When 75 liters are drawn and replaced with water, the ratio of wine to water becomes (x-75)/75.

When an additional 60 liters are drawn and replaced with water, the ratio becomes (x-75-60)/(75+60), which is equal to 3/2.

Simplifying the equation, we get (x-75-60)/(75+60) = 3/2. Solving for x, we find that the cask initially held 180 liters of wine.

User Peter HIRT
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