Question

For the cell shown, the measured cell potential, ecell, is -0.3703 V at 25 °C. The balanced reduction half reactions for the cell, and their respective standard reduction potential values, e°, are 2H+(aq) + 2e- → H₂(g) with e° = 0.00 V and Ca₂⁺+(aq) + 2e- → Cd(s) with e° = -0.403 V. Calculate the H+ concentration.

Answer 1

The H+ concentration can be calculated using the Nernst equation.

Step-by-step explanation:

The H+ concentration can be calculated using the Nernst equation, which is given as:

Ecell = Eºcell - (0.0592 V/n) * log([H+])

Given that ecell is -0.3703 V, eºcell is 0.00 V, and n is 2 (since 2 electrons are involved in the reduction half reaction), we can rearrange the equation to solve for [H+].

[H+] = 10^(-Ecell / (0.0592 V/n))

Substituting the given values:

[H+] = 10^(-(-0.3703 V) / (0.0592 V/2))

[H+] = 10^(-6.2267)

[H+] = 2.10 x 10^(-7) M