Final answer:
The Punnett square shows that all of Thelma and Joe's children will have freckles and be heterozygous. As freckles are a dominant trait, all of their children will have freckles and be heterozygous (Ff). So, the possible options for their children are:
Step-by-step explanation:
The Punnett square is a tool used in genetics to predict the possible outcomes of a cross between two individuals. In this case, Thelma is homozygous dominant for freckles (FF) and Joe does not have freckles (ff). The Punnett square for their offspring would look like this:
F f
F | FF | Ff
f | Ff | ff
As freckles are a dominant trait, all of their children will have freckles and be heterozygous (Ff). So, the possible options for their children are:
Freckles (Ff)
Using a Punnett square, we can determine that all children of Thelma (homozygous dominant for freckles) and Joe (non-freckled) will have freckles. The children's genotype will be Ff, which means they express the dominant freckled phenotype.
The question involves creating a Punnett square to show the possible genetic outcomes for the offspring of Thelma, who is homozygous dominant for freckles, and her husband, Joe, who does not have freckles. Since Thelma is homozygous dominant, her genotype for the freckle trait would be FF. Joe does not have freckles, so his genotype would be recessive, which is ff.
Here is the Punnett square for the cross of Thelma (FF) and Joe (ff):
FFfFf (Freckles)Ff (Freckles)fFf (Freckles)Ff (Freckles)
As we can see from the Punnett square, all the children will have the genotype Ff, indicating that they will have freckles since F is the dominant allele. There are no options for a child without freckles in this scenario because Joe, with genotype ff, can only contribute a recessive allele, and freckles are a dominant trait.