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An inflated playground ball is about 8 inches in diameter. What is the surface area of the ball rounded to the nearest ten square inches?

User Obelia
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Final answer:

The surface area of a playground ball with a diameter of 8 inches is approximately 200 square inches when rounded to the nearest ten.

Step-by-step explanation:

To calculate the surface area of a ball with a diameter of 8 inches, we use the formula for the surface area of a sphere, which is 4πr², where π is approximately 3.14 and r is the radius. Since the diameter is 8 inches, the radius is half that, which is 4 inches. Plugging the values into the formula gives us:

Surface Area = 4π(4 inches)²

≈ 4π(16 inches²)

≈ 4 × 3.14 × 16 inches²

≈ 201.06 inches²

We round this to the nearest ten to get a surface area of approximately 200 square inches.

User Uma Madhavi
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