Question

A manufacturing company produces steel housings for electrical equipment. The main component part of the housing is a steel trough that is made out of a 14-gauge steel coil. It is produced using a 250-ton progressive punch press with a wipe-down operation that puts two 90-degree forms in the flat steel to make the trough. The distance from one side of the form to the other is critical because of weather-proofing in outdoor applications. The data from a sample of 49 troughs follows. Construct a 95

Answer 1

To find the resistance of the coil, use the formula: R = (ρ * L) / A. Calculate the length of the wire, N*C, and the cross-sectional area of the wire, A = (π * r^2). Substitute the values into the resistance formula to find the resistance of the coil.

Step-by-step explanation:

To find the resistance of the coil, we need to use the formula:

R = (ρ * L) / A

• Where R is the resistance of the coil
• ρ is the resistivity of copper (1.68 x 10^-8 Ωm)
• L is the length of the wire (calculated by multiplying the number of turns by the circumference of the core)
• A is the cross-sectional area of the wire

First, we calculate the length of the wire:

L = N * C

• Where N is the number of turns (1000)
• C is the circumference of the core (calculated by multiplying the radius by 2π)

Next, we calculate the cross-sectional area of the wire:

A = (π * r^2)

• Where r is the radius of the wire (calculated by subtracting the insulation thickness from the core radius)

Finally, we substitute the values into the resistance formula and calculate the resistance of the coil.