Question

A jar of gumballs contains 5 blue, 3 yellow, 6 green, and 2 purple gumballs. If two gumballs are selected from the jar, what is the probability of selecting a green gumball and then a yellow gumball with replacement?

Answer 1

The probability of selecting a green gumball and then a yellow gumball with replacement is 9/128.

Step-by-step explanation:

To find the probability of selecting a green gumball and then a yellow gumball with replacement, we need to find the individual probabilities of each event and multiply them together.

1. There are 6 green gumballs in the jar of 16 total gumballs, so the probability of selecting a green gumball is 6/16.
2. After the first gumball is selected with replacement, there are still 16 gumballs in the jar, but now there are only 3 yellow gumballs. So the probability of selecting a yellow gumball is 3/16.

To calculate the probability of both events occurring, we multiply the probabilities: (6/16) * (3/16) = 18/256 and simplify the fraction to get the final probability of 9/128.