Question

A hummingbird has a mass of about 1.7 g. Suppose a hummingbird does 0.15 J of work against gravity so that it ascends straight up with a net acceleration of 1.2 m/s². How far up does it move? (Round your answer to the nearest tenth.)

Answer 1

The hummingbird moves approximately 8.8 meters upwards when it does 0.15 J of work against gravity with a mass of 1.7 g.

Step-by-step explanation:

To determine how far the hummingbird moves upwards, we can use the work-energy principle which states that work done on an object is equal to the change in its kinetic energy. Since the question indicates that the work is done against gravity, we can use the formula for gravitational work, W = mgh, where W is work, m is mass, g is the acceleration due to gravity, and h is the height. With the given work (W) of 0.15 J and the mass (m) of the hummingbird as 1.7 g (which we convert to kilograms by dividing it by 1000 to get 1.7 x 10-3 kg).

Assuming the acceleration due to gravity (g) is approximately 9.8 m/s2, we can rearrange the formula to solve for height (h):

h = W / (mg)

Plugging the values we have:

h = 0.15 J / ((1.7 x 10-3 kg) x 9.8 m/s2)

The resulting height (h) is approximately 8.8 meters when rounded to the nearest tenth.