143k views
5 votes
Write the slope-intercept form of the equation of a line that contains the point (-6, 7) and has a slope of -2/3.

User Schenz
by
8.4k points

1 Answer

0 votes

Final answer:

To write the slope-intercept form of the equation of a line, we can use the formula y = mx + b. For this line with a slope of -2/3 and containing the point (-6, 7), the equation is y = -2/3x + 3.

Step-by-step explanation:

To write the slope-intercept form of the equation of a line that contains the point (-6, 7) and has a slope of -2/3, we can use the formula y = mx + b. Here, m represents the slope and b represents the y-intercept. Since we have the slope and a point on the line, we can substitute these values into the equation.

Substituting the values, we have 7 = -2/3(-6) + b. Simplifying, we get 7 = 4 + b. To isolate b, we subtract 4 from both sides, giving us b = 3.

Therefore, the equation of the line in slope-intercept form is y = -2/3x + 3. The slope of the line is -2/3 and the y-intercept is 3.

User Hasternet
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories