Final answer:
There are 28 different ways to choose 6 bananas from a group of 8, as calculated using the combinations formula, 8C6.
Step-by-step explanation:
The question asks us to determine the number of ways to choose 6 bananas from a group of 8. This is a problem of combinations, where the order of selection does not matter. The formula for combinations is given by nCr = n! / (r!(n-r)!), where n is the total number of items to choose from, r is the number of items to choose, and '!' denotes factorial. A factorial of a number (e.g., 4!) is the product of all positive integers less than or equal to that number. For our problem, we have 8 bananas and we want to choose 6, so the calculation becomes 8C6 = 8! / (6!(8-6)!) = 8! / (6!2!) = (8×7)/(2×1) = 28. Therefore, there are 28 different ways to choose 6 bananas from a group of 8.