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Write the associated MIPS assembly code for the given C code.

int array[1000];
int a;
for (a = 0; a < 1000; a++)

array[a] = a * 2;

User Thikonom
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1 Answer

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Final answer:

To write the associated MIPS assembly code for the given C code, we define the array and variable a, initialize them, and use a loop to assign the value of a * 2 to each element of the array.

Step-by-step explanation:

To write the associated MIPS assembly code for the given C code, we should first start by declaring the array and the variable a in the .data section:

.data
array: .space 4000
a: .word 0

Next, we move the address of the array to a register and initialize the variable a to zero:

la $t0, array
li $t1, 0

Then, we can use a loop to iterate through the array and assign the value of a * 2 to each element:

loop:
mul $t2, $t1, 2
sw $t2, 0($t0)
addi $t0, $t0, 4
addi $t1, $t1, 1
blt $t1, 1000, loop

This code uses the mul instruction to multiply the value of a by 2, the sw instruction to store the result in the array, and the addi instruction to increment the address of the array and the value of a. The blt instruction is used to check if the value of a is less than 1000, and if it is, the loop continues.

User Hooman Bahreini
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