Final answer:
The speed of a 71 kg jogger with the same kinetic energy as that described in the content would be approximately 4.44 m/s, calculated using the kinetic energy formula.
Step-by-step explanation:
To determine the speed of a jogger who has a mass of 71 kg with the same kinetic energy as that of the content provided, we will use the information given about the astronomy instructor. It's stated that a 73-kg instructor running at about 4.4 m/s has a kinetic energy of about 700 joules. Kinetic energy (KE) is given by the equation KE = (1/2)mv2, where m is the mass and v is the velocity of the object. First, we calculate the kinetic energy for the jogger using the example of the instructor: KE = (1/2)*73 kg*(4.4 m/s)2 = 700 joules. We use this kinetic energy to find the speed of the jogger with a mass of 71 kg: (1/2)*71 kg*v2 = 700 joules, solving for v we get v2 = (2*700 joules) / 71 kg = 19.7183 m2/s2, therefore v = sqrt(19.7183) m/s ≈ 4.44 m/s. The speed of the jogger would be approximately 4.44 meters per second if they have the same kinetic energy as the content describing the astronomy instructor.