Question

What is the electrode potential of a half-cell produced by dissolving copper in water?

1) 0.32 V
2) 0.64 V
3) 0.16 V
4) 0.48 V

Answer 1

The electrode potential of a half-cell with copper in a 1 M CuSO4 solution is +0.337 V. The closest given option is 0.32 V, which is the correct choice for the copper half-cell potential in standard conditions.

Step-by-step explanation:

The electrode potential of a half-cell produced by dissolving copper in water can be determined from the standard electrode potential for the half-reaction Cu2+ (aq) + 2e- → Cu(s). According to the information provided, this standard electrode potential is measured to be +0.337 V when a copper electrode is placed in a 1 M CuSO4 solution and connected to a Standard Hydrogen Electrode (SHE) under standard-state conditions.

Therefore, the correct answer to the question is: 1) 0.32 V, which is the closest value to the actual measured potential of +0.337 V for this half-cell reaction.