Question

A car is moving upwards on the hill, inclined at 20 degrees with horizontal. This car is increasing its velocity at the rate of 25 km/h every 7 seconds. What is the magnitude of the force acting on the passenger if his mass is 70 kg?

Answer 1

The magnitude of the force acting on the passenger with a mass of 70 kg as the car increases its velocity on an incline at 25 km/h every 7 seconds is approximately 69.3 N, calculated using Newton's second law.

Step-by-step explanation:

To calculate the magnitude of the force acting on the passenger with a mass of 70 kg when the car is increasing its velocity up an incline, we will use Newton's second law of motion. First, we need to calculate the acceleration of the car. The car is increasing its speed at a rate of 25 km/h every 7 seconds. Therefore, we need to convert the rate into meters per second squared (m/s²).

25 km/h = 25 * 1000 m / (60 * 60) s = approximately 6.94 m/s.

Now, as the increase happens every 7 seconds, the acceleration (a) is:

a = Δv / Δt = 6.94 m/s / 7 s = 0.99 m/s².

Using the formula F = ma, where 'm' is the mass and 'a' is the acceleration, we can find the force (F) acting on the passenger:

F = 70 kg * 0.99 m/s² = 69.3 N (Newtons).

Note that this value does not take into consideration the effects of gravity and the inclination of the car, it represents a simplified calculation of force based solely on the passenger's mass and the car's acceleration.