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A ball of mass 0.300 kg is whirled in a horizontal circle at the end of a light string 75.0 cm long at a speed of 2.00 m/s. What is the centripetal force acting on the ball?

1) 0.900 N
2) 1.800 N
3) 2.700 N
4) 3.600 N

User Jwswart
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1 Answer

6 votes

Final Answer:

The centripetal force acting on the ball will be 2) 1.800 N. so Option 2 is correct.

Step-by-step explanation:

The centripetal force acting on the ball can be calculated using the formula for centripetal force, which is given by the equation F_c = m.v²/r , where m is the mass of the object, v is its velocity, and r is the radius of the circular path. In this scenario, the radius is equal to the length of the string,r = 0.750 m. The mass of the ball is m = 0.300 kg, and its velocity is v = 2.00 m/s. Plugging in these values, we get F_c = (0.300 kg . 2.00 m/s²)/0.750 m = 1.800 N.

The centripetal force is the force required to keep an object moving in a circular path. In this case, the ball is being whirled in a horizontal circle at a constant speed. The tension in the string provides this force, acting as the centripetal force. The formula F_c = m.v²/r is derived from Newton's second law and is applicable to any object moving in a circular path. It shows that the centripetal force is directly proportional to the mass of the object and the square of its velocity, while inversely proportional to the radius of the circular path.

In summary, the centripetal force acting on the ball is 1.800 N. This force is necessary to keep the ball moving in its circular path, and the tension in the string provides this force, maintaining the dynamic equilibrium required for circular motion.

User StevenR
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