Question

A 58.7 g sample of iron is put into a calorimeter that contains 200.0 g of water. The iron sample starts off at 94.2°C and the temperature of the water starts off at 21.0°C. When the temperature of the water stops changing, it is 24.1°C. The pressure remains constant. Calculate the specific heat capacity of iron according to this experiment.

Answer 1

To calculate the specific heat capacity of the metal, use the equation: heat = mcAT, where m is the mass of the metal, c is the specific heat capacity, and AT is the change in temperature.

Step-by-step explanation:

To calculate the specific heat capacity of the metal, we can use the heat formula: heat = mcΔT, where m is the mass of the metal, c is the specific heat capacity, and ΔT is the change in temperature.

Using the given information, we can calculate ΔT by subtracting the initial temperature from the final temperature: ΔT = 39°C - 25°C = 14°C.

Now, we can substitute the known values into the formula to find the specific heat capacity of the metal: heat = (m metal) × (c metal) × (ΔT), where heat = 0 (since no heat is lost or gained), m metal = 34.5 g, ΔT = 14°C. Solving for c metal, we get c metal = 0 J/(g°C).