Question

23.0 ml of 0.1 M KOH solution is used to neutralize a 3.0 ml sample of acetic acid solution. What is the molarity of the acetic acid solution?

Answer 1

The molarity of the acetic acid solution is 0.77 M.

Step-by-step explanation:

To find the molarity of the acetic acid solution, we can use the equation:

M1V1 = M2V2

Where M1 is the molarity of KOH solution, V1 is the volume of KOH solution used, M2 is the molarity of acetic acid solution, and V2 is the volume of acetic acid solution used.

Plugging in the values:

(0.1 M)(23.0 mL) = M2(3.0 mL)

Simplifying the equation:

2.3 mL = M2(3.0 mL)

Dividing both sides by 3.0 mL:

M2 = 0.77 M