Question

what is the amount in grams of edta needed to make 346 ml of a 0.02 m edta solution. the molar mass of edta is 374 g/mol. (only enter numeric value in the answer, do not include the unit)

Answer 1

To prepare a 346 mL of a 0.02 M EDTA solution, 2.6 grams of EDTA (rounded to one decimal place) are needed, based on the calculation involving molarity, volume, and the molar mass of EDTA.

Step-by-step explanation:

The amount in grams of EDTA needed to make 346 mL of a 0.02 M EDTA solution is calculated by first determining the moles of EDTA needed and then converting that amount to grams using the molar mass of EDTA. The number of moles is found by molarity × volume in liters (0.02 M × 0.346 L). Once the moles are calculated, the mass in grams is found by multiplying the moles of EDTA by its molar mass (374 g/mol).

To find the mass of EDTA needed:

• Moles of EDTA = Molarity × Volume = 0.02 mol/L × 0.346 L = 0.00692 mol
• Mass of EDTA = Moles of EDTA × Molar Mass of EDTA = 0.00692 mol × 374 g/mol = 2.58848 g

The calculated mass in grams of EDTA needed is therefore rounded to one significant figure past the decimal (as given by the volumes significant figures), which equals 2.6 g.